Download Civil Discipline-Specific Review for the FE EIT Exam by Robert Kim MSCE PE, Thomas A. Spriggs MSCE, Michael R. PDF

By Robert Kim MSCE PE, Thomas A. Spriggs MSCE, Michael R. Lindeburg PE

The Civil Discipline-Specific overview is designed to provide you the easiest education for the civil component to the FE examination. sixty one perform difficulties plus 4-hour afternoon perform assessments complement your learn regime and assist you investigate your readiness for the examination. while you are taking the civil part of the FE examination, Civil Discipline-Specific evaluation offers you the centred perform and guidance you want to pass.Topics coated building administration Environmental Engineering Hydraulics & Hydrologic platforms fabrics Soils Mechanics & Foundations Structural research Structural layout Surveying Transportation _____________________________Since 1975 greater than 2 million humans getting ready for his or her engineering, surveying, structure, LEED®, inside layout, and panorama structure assessments have entrusted their examination prep to PPI. for additional info, stopover at us at  

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What is the following type of model called? c The EST of an activity is calculated as the maximum of the EFTs of the activities preceding it. For example, activity A has no activities preceding it, so it has an EST of day 0. The EFT of this activity is end a bubble (activity-an-node) network an arrow (activity-an-arrow) network a PERT chart a bar (Gantt) chart Solution This is called a bubble (activity-an-node) network. The answer is A. ions, in days, given for each activity in the diagram shown.

For activity A EFTA = day 0 +1d = day 1 Activity C is preceded by two activities, start and activity A, so the EST of C is the maximum EFT of the two. The EST of activity C is day 1 and its EFT is day 8. The minimum project duration is 19 d. 0 m, A = 60 X 10-4 m"). The rail was installed without allowance for expansion and the ends were constrained by adjacent rails. 7 x 10-6 1rC. What is the compressive force in the rail at 25°C? (A) 281 (B) 285 (C) 291 (D) 295 kN kN kN kN Solution The thermal strain is found as Activity F is preceded only by activity D.

The total float time (TF) of an activity is determined by either subtracting the EFT from the LFT or subtracting the EST from the LST. For example, the TF of activity G is TF = LFT - EFT = day 17 - day 10 Making a summary table helps to organize these results. -CD-G-encl. Because activity G is along the critical path, the float time for this activity is a d. The answer is A. 5 activities A through G. Each activity's duration is given in days. ) TF (d) 14 5 16 14 16 17 17 17 6 0 9 0 8 0 7 8 The critical path is the path that passes through the activities that result in a TF of 0 d.

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