Download An Introduction to Ordinary Differential Equations (Dover by Earl A. Coddington PDF

By Earl A. Coddington

"Written in an admirably cleancut and cost-effective style." - Mathematical Reviews.
This concise textual content bargains undergraduates in arithmetic and technology an intensive and systematic first direction in basic differential equations. Presuming a data of uncomplicated calculus, the publication first studies the mathematical necessities required to grasp the fabrics to be presented.
The subsequent 4 chapters absorb linear equations, these of the 1st order and people with consistent coefficients, variable coefficients, and standard singular issues. The final chapters deal with the lifestyles and distinctiveness of ideas to either first order equations and to platforms and n-th order equations.
Throughout the booklet, the writer includes the idea a long way sufficient to incorporate the statements and proofs of the better lifestyles and forte theorems. Dr. Coddington, who has taught at MIT, Princeton, and UCLA, has integrated many workouts designed to strengthen the student's strategy in fixing equations. He has additionally integrated difficulties (with solutions) chosen to sharpen knowing of the mathematical constitution of the topic, and to introduce numerous suitable themes now not coated within the textual content, e.g. balance, equations with periodic coefficients, and boundary worth difficulties.

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Extra info for An Introduction to Ordinary Differential Equations (Dover Books on Mathematics)

Sample text

We can solve all those first-order differential equations in which time does not appear explicitly. Now, suppose we have a differential equation of the form ely/dt= f(y / I), such as, for example, the equation ely / dt = sin(y / I). Differential equations of this form are called homogeneous equations. Since the right-hand side only depends on the single variable y / t. it suggests itself to make the substitution y /1 = V or y = tv. (a) Show that this substitution replaces the equation dy / dt = f(y / t) by the equivalent equation tdv/dt+v=f(v), which is separable.

The general solution of the differential equation must be left in the form e l + 3ry + siny = c since we cannot find y explicitly as a function of t from this equation. Second Method: From (ii), CP(t,y) = 3ty + siny + k(t). Differentiating this expression with respect to t, and using (i) we obtain that 3y+k'(t)=3y+e'. Thus, k(t)=e ' and CP(t,y)=3ty+siny+e '. Third Method: From (i) and (ii) cp(t,y) = e l + 3ty + h(y) and cp(t,y) =3ty +siny + k( t). Comparing these two expressions for the same function CP(t,y) it is obvious 51 1 First-order differential equations that h(y)=siny and k(t)=e l.

Differentiating this expression with respect to t and using (i) we obtain (t 4 + 4t 3 )e t +Y + k'( t) =4t 3e t +y + t 4e t +y + 2t. Thus, k(t)= t 2 and the general solution of the differential equation is (t,y)=t4e t +Y +y2+t 2=c. Setting t=O andy=l in this equation yields c = 1. Thus, the solution of our initial-value problem is defined implicitly by the equation t 4e l +Y + t 2+ y2 = 1. Suppose now that we are given a differential equation dy M(t,y)+ N(t,y) dt =0 (7) which is not exact. Can we make it exact?

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